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Let (X,Y) have constant probability density on the triangle defined by x > 0,y > 0,x+y < 1. Then the pdf of Z=X+Y is p(z) defined for 0 < z < 1 by:
  • p(z) = 3 z2
  • p(z) = z
  • p(z) = z/2
  • p(z) = 2(1-z)
  • p(z) = 1
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    Carlos Rodriguez <carlos@math.albany.edu>
    This problem was contributed by a student. It is offered as it is with no warranty of any kind
    Last modified:Thu Sep 18 2008 15:15:37 GMT-0400 (Eastern Daylight Time)