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When the motion of a microscopic particle in a liquid or a gas is observed, it is seen that the motion is irregular because the particle collides frequently with other particles. The probability model for this motion, which is called Brownian motion, is as follows: A coordinate system is chosen in the liquid or gas. Suppose that the particle is at the origin of this coordinate system at time t = 0; and let (X,Y,Z) denote the coordinates of the particle at any time t > 0. The random variables X,Y,and Z are i.i.d. and each of them has a normal distribution with mean 0 and variance (sigma^2)t. Find the probability that at time t = 2 the particle will lie within a sphere of radius 3.5sigma whose center is at the origin. The closest value is:
  • .95
  • .10
  • .90
  • .05
  • .99
  • *****
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    Carlos Rodriguez <carlos@math.albany.edu>
    This problem was contributed by a student. It is offered as it is with no warranty of any kind
    Last modified: Wed May 13 12:29:11 EDT 1998