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A manufacturer of TVs needs 72 resistors, 200 capacitors, and 80 diodes in order to build a particular model. The manufacturer can buy the components from three different electronic distributors. The first distributor packages 4 resistors, 10 capacitors, and 10 diodes in one grab bag. The second distributor packages 8 resistors, 20 capacitors, and 0 diodes in his grab bag. The third distributor's grab bag consists of 12 resistors, 40 capacitors, and 20 diodes. Use Cramer's rule to find x,y,z, the required number of grab bags that are needed from each of the three distributors to build the TV.
  • x = 4, y = 8, z = 2
  • x = 8, y = 4, z = 1
  • x = 1, y = 2, z = 3
  • x = 4, y = 4, z = 2
  • x = 4, y = 1, z = 3
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    Carlos Rodriguez <carlos@math.albany.edu>
    This problem was contributed by a student. It is offered as it is with no warranty of any kind
    Last modified:Tue Jun 04 12:10:29 GMT-0400 (EDT) 2002