
Let 
> u := [2,1]: v:= [3,4]:
Sketch the vector,


We can write a function for finding the vector for the different values of c. 
> mix := c > evalm(c*u+(1c)*v);
mix := c > evalm(c u + (1  c) v)
The four vectors are, 
> m0:=mix(0); m1:= mix(1/4); m2:= mix(3/4); m3 := mix(1);
m0 := [3, 4] m1 := [7/4, 13/4] m2 := [3/4, 7/4] m3 := [2, 1]
These vectors are along the segment from v to u.
m1 is 1/4 of the way along and m2 is 3/4 of the way along uv
(look at the picture).

This shows that if the initial point fo cu+(1c)v for
0 