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Computing Limits


*****

Problem:

Find the following limit

> ;

                                       x - y
                        lim          ------------
                       x,y -> (3,4)    2    2 1/2
                                     (x  + y )


Solution:


The function is continuous at (3,4) so computing the limit is just a matter of evaluating the function at (3,4).

> f := (x,y) -> (x-y)/sqrt(x^2+y^2):
> `f(3,4)` = f(3,4);

                                 f(3,4) = -1/5

Link to the commands in this file
Carlos Rodriguez <carlos@math.albany.edu>
Last modified: Thu Mar 22 15:33:30 EST 2001