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Domain and Range


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Problem:

Find the Domain D and Range R for the function,

> f := (x,y) -> sqrt(x-y);


Solution:


Clearly this function is defined where the square root is defined, i.e. for all non negative real numbers.
D = {(x,y) : x >= y}

The range is the set of values that f(x,y) can take. We have,

R = {z : z >= 0}
since f(x,y) is defined as the POSITIVE square root of (x-y).


Link to the commands in this file
Carlos Rodriguez <carlos@math.albany.edu>
Last modified: Wed Mar 21 12:25:44 EST 2001