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Find the equation of the plane that contains the point (1,1,-1) and has the normal vector -i-2j+3k. x+2y-3z = 6 -x-2y+3z = 0 x+y-z = 0 x+y-z = 6 x+2y-3z = 0

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Carlos Rodriguez <carlos@math.albany.edu>

This problem was contributed by a student. It is offered as it is with no warranty of any kind
Last modified:Mon Sep 25 15:02:48 GMT-0400 (EDT) 2000